x^2+3x-96=12

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Solution for x^2+3x-96=12 equation:


Simplifying
x2 + 3x + -96 = 12

Reorder the terms:
-96 + 3x + x2 = 12

Solving
-96 + 3x + x2 = 12

Solving for variable 'x'.

Reorder the terms:
-96 + -12 + 3x + x2 = 12 + -12

Combine like terms: -96 + -12 = -108
-108 + 3x + x2 = 12 + -12

Combine like terms: 12 + -12 = 0
-108 + 3x + x2 = 0

Factor a trinomial.
(-12 + -1x)(9 + -1x) = 0

Subproblem 1

Set the factor '(-12 + -1x)' equal to zero and attempt to solve: Simplifying -12 + -1x = 0 Solving -12 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1x = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1x = 0 + 12 -1x = 0 + 12 Combine like terms: 0 + 12 = 12 -1x = 12 Divide each side by '-1'. x = -12 Simplifying x = -12

Subproblem 2

Set the factor '(9 + -1x)' equal to zero and attempt to solve: Simplifying 9 + -1x = 0 Solving 9 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1x = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1x = 0 + -9 -1x = 0 + -9 Combine like terms: 0 + -9 = -9 -1x = -9 Divide each side by '-1'. x = 9 Simplifying x = 9

Solution

x = {-12, 9}

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